TS Police SI Mains 2023 Paper 3 · Question 16

Question 16 of the TSLPRB SI Final Written Examination 2023, Paper III (Arithmetic & Reasoning) (8 April 2023). Try it first, then open the answer and explanation.

1. SI Mains 2023 Paper III · Q16 · Arithmetic · Numbers & Simplification

   If 3^(x+1) − 3^x = 162 then x² − 2x − 8 =

   1. 0
   2. 8
   3. 3
   4. 15

   ఒకవేళ 3^(x+1) − 3^x = 162 అయితే x² − 2x − 8 =

   1. 0
   2. 8
   3. 3
   4. 15
   Show answer

   Answer: (1) 0

   సమాధానం: (1) 0

   3^(x+1) − 3^x = 3^x(3 − 1) = 2 × 3^x = 162, so 3^x = 81 and x = 4. Then x² − 2x − 8 = 16 − 8 − 8 = 0.

   3^(x+1) − 3^x = 3^x(3 − 1) = 2 × 3^x = 162, కాబట్టి 3^x = 81 మరియు x = 4. అప్పుడు x² − 2x − 8 = 16 − 8 − 8 = 0.

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