TGPSC HMWSSB Manager 2015 Paper 2 · Question 131
Question 131 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.
A cable carrying a load of w/unit run is stretched between supports L apart. The supports are at the same level and the central dip is h. The greatest and least tensions in the cable are ______.
- wL/2, wL²/8h
- √((wL/2)²+(wL²/8h)), wL²/16h
- √((wL/2)²+(wL²/8h)), wL²/8h
- √((wL/2)²+(wL²/2h)), wL²/8h
Show answer
Answer: (3) √((wL/2)²+(wL²/8h)), wL²/8h
The horizontal tension H = (wL²/8)/h = wL²/8h is the least tension, at the lowest point, and each support also has a vertical reaction wL/2. The greatest tension, at the supports, is √((wL/2)² + (wL²/8h)²); the booklet's options omit the square on the second term.