UPSC CAPF (AC) 2026 Paper I · Question 58
Question 58 of the UPSC CAPF (AC) 2026 Paper I (19 July 2026). Try it first, then open the answer and explanation.
A metallic cylindrical disc of radius 7 cm is melted and 22 square-shaped solids of the same thickness are made. If l cm is the side length of these squares, then (in cm)
- 2.5 < l < 2.6
- 2.6 < l < 2.7
- 2.7 < l < 2.8
- 2.8 < l < 2.9
7 cm त्रिज्या वाली एक धात्विक बेलनाकार चक्रिका (cylindrical disc) को पिघलाया जाता है और समान मोटाई के 22 वर्गाकार ठोस (solids) बनाए जाते हैं। यदि इन वर्गों की भुजा की लंबाई l cm है, तो (cm में)
- 2.5 < l < 2.6
- 2.6 < l < 2.7
- 2.7 < l < 2.8
- 2.8 < l < 2.9
Show answer
Answer: (2) 2.6 < l < 2.7
उत्तर: (2) 2.6 < l < 2.7
With the same thickness t, volume is conserved: (22/7) × 7² × t = 22 × l² × t, so 154 = 22l² and l² = 7. Hence l = √7 ≈ 2.646 cm, which lies between 2.6 and 2.7.