UPSC CAPF (AC) 2026 Paper I · Question 113

Question 113 of the UPSC CAPF (AC) 2026 Paper I (19 July 2026). Try it first, then open the answer and explanation.

1. CAPF 2026 · P-I · Q113 · General Science · Physics

   If the relative density of gold is 19.3 and the density of water is 10^6 g/m³, what will be the density of gold in SI units?

   1. 1930 kg/m³
   2. 19300 kg/m³
   3. 193000 kg/m³
   4. 1.93 × 10^6 kg/m³

   यदि स्वर्ण का आपेक्षिक घनत्व 19.3 है और जल का घनत्व 10^6 g/m³ है, तो SI मात्रक (unit) में स्वर्ण का घनत्व क्या होगा?

   1. 1930 kg/m³
   2. 19300 kg/m³
   3. 193000 kg/m³
   4. 1.93 × 10^6 kg/m³
   Show answer

   Answer: (2) 19300 kg/m³

   उत्तर: (2) 19300 kg/m³

   Density of water = 10^6 g/m³ = 10³ kg/m³ = 1000 kg/m³. Density of gold = relative density × density of water = 19.3 × 1000 = 19300 kg/m³.

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