TGPSC HMWSSB Manager 2015 Paper 2 · Question 89

Question 89 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.

1. Manager 2015 Paper 2 (Civil) · Q89 · Environmental Engineering · Sewerage & Wastewater Treatment

   Lower Food to Micro-organism (F/M) ratio in a conventional activated treatment plant will mean

   1. Lower BOD removal
   2. Higher BOD removal
   3. No effect on BOD removal
   4. Medium BOD removal
   Show answer

   Answer: (2) Higher BOD removal

   At a low F/M ratio the micro-organisms are starved of food relative to their number, so they consume the organic matter more completely, giving higher BOD removal (as in extended aeration), though with a larger tank.

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