TGPSC HMWSSB Manager 2015 Paper 2 · Question 75

Question 75 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.

1. Manager 2015 Paper 2 (Civil) · Q75 · Fluid Mechanics & Hydraulics · Hydraulics & Hydraulic Machines

   For a uniform flow with a depth of 0.6m and Froude number of 2.0 in a rectangular channel, the specific energy will be

   1. 2.4m
   2. 0.8m
   3. 2.6m
   4. 1.8m
   Show answer

   Answer: (4) 1.8m

   Fr² = V²/(gy) = 4, so V²/2g = 2y = 1.2 m and E = y + V²/2g = 0.6 + 1.2 = 1.8 m.

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