TGPSC HMWSSB Manager 2015 Paper 2 · Question 49

Question 49 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.

1. Manager 2015 Paper 2 (Civil) · Q49 · Fluid Mechanics & Hydraulics · Hydraulics & Hydraulic Machines

   A rectangular channel has a width of 1.8m and carries a discharge of 1.8m³/sec at a depth of 0.20m. The specific energy is

   1. 1.03m
   2. 1.47m
   3. 1.87m
   4. 2.0m
   Show answer

   Answer: (2) 1.47m

   Velocity V = Q/(by) = 1.8/(1.8 × 0.20) = 5 m/s, so velocity head = 5²/(2 × 9.81) = 1.274 m. Specific energy E = y + V²/2g = 0.20 + 1.274 = 1.47 m.

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