TGPSC HMWSSB Manager 2015 Paper 2 · Question 109

Question 109 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.

1. Manager 2015 Paper 2 (Civil) · Q109 · Strength of Materials & Structural Analysis · Strength of Materials

   The stiffness of a close coiled spring is more when ______.

   1. wire diameter, rigidity modulus are more and mean radius, number of turns are lesser
   2. number of turns, rigidity modulus are more and mean radius, wire diameter are lesser
   3. mean radius, rigidity modulus are more and wire diameter, number of turns are lesser
   4. rigidity modulus is more and wire diameter, mean radius, number of turns are lesser
   Show answer

   Answer: (1) wire diameter, rigidity modulus are more and mean radius, number of turns are lesser

   Stiffness of a close-coiled helical spring k = Gd⁴/(64R³n), so it increases with larger wire diameter d and rigidity modulus G, and with smaller mean coil radius R and fewer turns n.

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