UPSC CAPF (AC) 2025 Paper I · Question 112

Question 112 of the UPSC CAPF (AC) 2025 Paper I (3 August 2025). Try it first, then open the answer and explanation.

1. CAPF 2025 · P-I · Q112 · General Science · Physics

   The potential difference between the terminals of an electrical heating device is 40 V, when it draws a current of 2 A from the source. Which one of the following is the correct value of current drawn by the heating device if the potential is increased to 140 V?

   1. 7 A
   2. 5 A
   3. 4 A
   4. 2 A

   किसी विद्युत् तापन उपकरण (heating device) के टर्मिनलों के बीच विभवांतर 40 V है, जब यह स्रोत से 2 A की धारा लेता है। यदि विभव को 140 V तक बढ़ा दिया जाए, तो तापन उपकरण द्वारा ली गई धारा का सही मान निम्नलिखित में से कौन-सा है?

   1. 7 A
   2. 5 A
   3. 4 A
   4. 2 A
   Show answer

   Answer: (1) 7 A

   उत्तर: (1) 7 A

   By Ohm's law the resistance is R = V/I = 40/2 = 20 ohm; with the same resistance at 140 V, I = 140/20 = 7 A.

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