TS Police SI Mains 2023 Paper 3 · Question 6
Question 6 of the TSLPRB SI Final Written Examination 2023, Paper III (Arithmetic & Reasoning) (8 April 2023). Try it first, then open the answer and explanation.
√(142 + 116 ÷ √841 − ∛2197 × (125)^(1/3)) =
- 25
- 16
- 9
- 4
√(142 + 116 ÷ √841 − ∛2197 × (125)^(1/3)) =
- 25
- 16
- 9
- 4
Show answer
Answer: (3) 9
సమాధానం: (3) 9
√841 = 29, so 116 ÷ 29 = 4; ∛2197 = 13 and (125)^(1/3) = 5, so 13 × 5 = 65. The value is √(142 + 4 − 65) = √81 = 9.
√841 = 29, కాబట్టి 116 ÷ 29 = 4; ∛2197 = 13 మరియు (125)^(1/3) = 5, కాబట్టి 13 × 5 = 65. విలువ √(142 + 4 − 65) = √81 = 9.