TGPSC HMWSSB Manager 2015 Paper 2 · Question 99

Question 99 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.

1. Manager 2015 Paper 2 (Civil) · Q99 · Strength of Materials & Structural Analysis · Structural Analysis

   The correct combination of conditions that defines a rigid joint is ______ i) All members meeting at the joint are rigid. ii) All deflections and rotations at the joint are zero. iii) All members meeting at the joint undergo same deflections at that joint. iv) All members meeting at the joint undergo same rotations at that joint.

   1. i, ii
   2. i, iii
   3. ii, iv
   4. iii, iv
   Show answer

   Answer: (4) iii, iv

   A rigid joint keeps the angles between the connected members unchanged, so all member ends at the joint have the same displacement and the same rotation; the joint itself may still deflect and rotate (ii is a fixed support), and the members need not be rigid (i).

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