TGPSC HMWSSB Manager 2015 Paper 2 · Question 91

Question 91 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.

1. Manager 2015 Paper 2 (Civil) · Q91 · Strength of Materials & Structural Analysis · Strength of Materials

   A rectangular box made with thin uniform plate measures 2000mm x 1000mm x 1000mm. When the box is subjected to certain internal pressure, the dimensions in respective directions have changed by +2.0mm, -1mm and +1mm. The change in the volume of the box is ______.

   1. 2.0 × 10⁶ mm³
   2. 1.0 × 10⁶ mm³
   3. 2.0 × 10³ mm³
   4. 2.0 × 10⁵ mm³
   Show answer

   Answer: (1) 2.0 × 10⁶ mm³

   Volumetric strain = 2/2000 − 1/1000 + 1/1000 = 0.001, and V = 2000 × 1000 × 1000 = 2×10⁹ mm³, so ΔV = 0.001 × 2×10⁹ = 2.0×10⁶ mm³.

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