TGPSC HMWSSB Manager 2015 Paper 2 · Question 77
Question 77 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.
A sedimentation tank 6m wide, 15m long and 3m water depth is treating 2MLD of water. The surface overflow rate in lt/hr/m² is
- 858
- 926
- 1028
- 748
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Answer: (2) 926
Surface overflow rate = Q/(plan area) = 2×10⁶ litres/day ÷ (6 × 15 = 90 m²) = 22,222 lt/day/m² ÷ 24 ≈ 926 lt/hr/m²; the depth does not enter the calculation.