TGPSC HMWSSB Manager 2015 Paper 2 · Question 63

Question 63 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.

1. Manager 2015 Paper 2 (Civil) · Q63 · Fluid Mechanics & Hydraulics · Fluid Mechanics

   The velocity gradient is 1000/s. The viscosity is 1.2×10⁻⁴ N-s/m². The shear stress is

   1. 0.12N/m²
   2. 1.2×10⁻⁷ N/m²
   3. 12N/m²
   4. 12×10⁻⁵ N/m²
   Show answer

   Answer: (1) 0.12N/m²

   By Newton's law of viscosity τ = μ(du/dy) = 1.2×10⁻⁴ × 1000 = 0.12 N/m².

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