TGPSC HMWSSB Manager 2015 Paper 2 · Question 53
Question 53 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.
A volume of 3×10⁶ m³ of groundwater was pumped out from an unconfined aquifer, uniformly over an area of 5km². The pumping lowered the water table from initial level of 102m to 99m. The specific yield of the aquifer is
- 0.20
- 0.30
- 0.40
- 0.50
Show answer
Answer: (1) 0.20
Specific yield = volume drained / (area × fall of water table) = 3×10⁶ / (5×10⁶ × 3) = 0.20.