TGPSC HMWSSB Manager 2015 Paper 2 · Question 19

Question 19 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.

1. Manager 2015 Paper 2 (Civil) · Q19 · Transportation Engineering · Highway Engineering

   Calculate the Equivalent Axle load factor (EALF) for single axle load of 10 tons using fourth power formula.

   1. 2.26
   2. 22.60
   3. 1.23
   4. 11.23
   Show answer

   Answer: (1) 2.26

   By the fourth power rule, EALF = (axle load/standard axle load)⁴. With the standard single axle of 8.16 t (80 kN), EALF = (10/8.16)⁴ = 1.2255⁴ ≈ 2.26.

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