TGPSC HMWSSB Manager 2015 Paper 2 · Question 127
Question 127 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.
For a fixed beam of span L and uniform flexural rigidity EI, with both supports at same level, the support at right rotate by α radians anti clockwise. The support reactions at left and right supports (assuming upward displacement and anti clockwise rotations as positive) respectively are ______.
- 6EI α/L², 2EI α/L, 6EI α/L², 2EI α/L
- 6EI α/L², 4EI α/L, - 6EI α/L², 2EI α/L
- 6EI α/L², 2EI α/L, - 6EI α/L², 4EI α/L
- 6EI α/L², 2EI α/L, - 6EI α/L², 2EI α/L
Show answer
Answer: (3) 6EI α/L², 2EI α/L, - 6EI α/L², 4EI α/L
Rotating the right end by α induces a moment 4EIα/L at that end and a carry-over moment 2EIα/L at the left end, both anticlockwise. These end moments (total 6EIα/L) are balanced by a couple of vertical reactions 6EIα/L², upward at the left and downward at the right, giving 6EIα/L², 2EIα/L, −6EIα/L², 4EIα/L.