TGPSC HMWSSB Manager 2015 Paper 2 · Question 101
Question 101 of the TSPSC Manager (Engineering), HMWSSB, 2015: Paper 2 (Civil Engineering) (1 November 2015). Try it first, then open the answer and explanation.
In the moment distribution method of plane frame analysis, the distribution factor for a member at a joint depends on ______ combination of conditions. i) The slenderness ratio of all the members meeting at the joint. ii) The flexural rigidity of all the members meeting at the joint. iii) The I/L values of each member meeting at the joint. iv) Support conditions at the farther ends of members meeting at the joint.
- ii, iii
- i, iii
- iii, iv
- i, iv
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Answer: (3) iii, iv
The distribution factor of a member is its stiffness divided by the sum of the stiffnesses of all members at the joint, where stiffness is 4EI/L for a far end fixed and 3EI/L for a far end hinged. So it depends on the relative I/L values and on the far-end support conditions; slenderness ratio plays no part.