UPSC CAPF (AC) 2024 Paper I · Question 47
Question 47 of the UPSC CAPF (AC) 2024 Paper I (4 August 2024). Try it first, then open the answer and explanation.
The angle (in degrees) made by a sector having area one-sixth of the area of a semicircle is
- 15°
- 30°
- 45°
- 60°
किसी अर्धवृत्त के क्षेत्रफल के छठवें भाग के बराबर क्षेत्रफल वाले त्रिज्यखंड द्वारा बनाया गया कोण (डिग्री में) क्या होगा?
- 15°
- 30°
- 45°
- 60°
Show answer
Answer: (2) 30°
उत्तर: (2) 30°
Area of sector = (θ/360°) × πr² must equal (1/6) × (πr²/2) = πr²/12. So θ/360° = 1/12, giving θ = 30°.