TS Police Constable Prelims 2022 · Question 74
Question 74 of the TSLPRB Police Constable Preliminary Written Test 2022 (28 August 2022). Try it first, then open the answer and explanation.
The escape velocity on the surface of the earth is
- 9.8 km/s
- 11.2 km/s
- 19.6 km/s
- 4.9 km/s
భూమి ఉపరితలంపై పలాయన వేగము విలువ
- 9.8 km/s
- 11.2 km/s
- 19.6 km/s
- 4.9 km/s
Show answer
Answer: (2) 11.2 km/s
సమాధానం: (2) 11.2 km/s
Escape velocity v = √(2gR) = √(2 × 9.8 × 6.4 × 10^6) m/s ≈ 11,200 m/s, i.e. about 11.2 km/s. 9.8 is the value of g in m/s², not a velocity.