APPSC Group-I Prelims 2019 Paper II · Question 28
Question 28 of the APPSC Group-I Prelims 2019 Paper II (26 May 2019). Try it first, then open the answer and explanation.
The value of 1/(1+√2) + 1/(√2+√3) + 1/(√3+√4) + ... + 1/(√15+√16)
విలువ కనిపెట్టండి 1/(1+√2) + 1/(√2+√3) + 1/(√3+√4) + ... + 1/(√15+√16)
Show answer
Answer: 3
సమాధానం: 3
Rationalising each term, 1/(√n + √(n+1)) = √(n+1) − √n. The sum telescopes to √16 − √1 = 4 − 1 = 3.